x^-14=8/x

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Solution for x^-14=8/x equation:



x^-14=8/x
We move all terms to the left:
x^-14-(8/x)=0
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
x^-(+8/x)-14=0
We add all the numbers together, and all the variables
x-(+8/x)-14=0
We get rid of parentheses
x-8/x-14=0
We multiply all the terms by the denominator
x*x-14*x-8=0
We add all the numbers together, and all the variables
-14x+x*x-8=0
Wy multiply elements
x^2-14x-8=0
a = 1; b = -14; c = -8;
Δ = b2-4ac
Δ = -142-4·1·(-8)
Δ = 228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{57}}{2*1}=\frac{14-2\sqrt{57}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{57}}{2*1}=\frac{14+2\sqrt{57}}{2} $

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